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<title><![CDATA[kimho의 Web Programming>Kimho의 MySQL]]></title>
<link>http://kimho.ohpy.com/3210/0</link>
<description><![CDATA["Kimho의 PHP5 웹 프로그래밍"의 저자이자 오피닷컴(<a href="http://www.ohpy.com" target="_blank">www.ohpy.com</a>)의 개발 파트장인 김호(kimho)의 홈페이지입니다.^^]]></description>
<language>en</language>
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<pubDate>Wed, 03 Dec 2008 11:36:49 +0900</pubDate>
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<title>Chapter 22 김호보드 구현</title>
<link>http://kimho.ohpy.com/3210/38</link>
<description>22과 김호보드 게시판 구현할려면 어떻게 해야되나요? 자세한 답변 부탁드립니다.</description>
<author>황현철</author>
<pubDate>Mon, 04 Jun 2007 15:29:08 +0900</pubDate>
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<title>207페이지 질문입니다.</title>
<link>http://kimho.ohpy.com/3210/37</link>
<description>&lt;P&gt;오늘도 계속해보다가 의문점이 생겨서 질문드립니다.&lt;/P&gt;
&lt;P&gt;&amp;nbsp;&lt;/P&gt;
&lt;P&gt;207페이지 첫번째 열에서 &lt;/P&gt;
&lt;P&gt;insert into settest values ('bcd,xyz');&lt;/P&gt;
&lt;P&gt;이렇게 쿼리를 실행하면 에러가 나옵니다.. 책에서는 실행이 되는걸로 나오는데요..&lt;/P&gt;
&lt;P&gt;전페이지에서 칼럼을 만들때.. set('abc','bcd','cde')로 하고 xyz가 들어가면 에러가 나지 않나요?&lt;/P&gt;</description>
<author>hurbert</author>
<pubDate>Tue, 22 May 2007 17:00:05 +0900</pubDate>
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<title>아래질문에 대한 문제의 갭쳐화면입니다.</title>
<link>http://kimho.ohpy.com/3210/36</link>
<description>&lt;P&gt;&lt;A title=www.ohpy.com href=&quot;http://pic1.ohpy.com/up/elbbs/2007/05/17/8/2004182980/mysql.jpg&quot; target=_blank rel=lightbox&gt;&lt;IMG id=195207 alt=&quot;&quot; src=&quot;http://pic1.ohpy.com/up/elbbs/2007/05/17/8/2004182980/mid_mysql.jpg&quot; border=0&gt;&lt;/A&gt;&lt;/P&gt;
&lt;P&gt;&amp;nbsp;&lt;/P&gt;
&lt;P&gt;몇번을 해봐도 똑같은 에러메세지가 나오는데.. 이상하네요 ^^ &lt;/P&gt;
&lt;P&gt;primary key 설정때 id만 넣으면 되고요..&lt;/P&gt;</description>
<author>hubert</author>
<pubDate>Thu, 17 May 2007 11:47:41 +0900</pubDate>
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<title>primary key와 auto_increment 질문이요</title>
<link>http://kimho.ohpy.com/3210/35</link>
<description>&lt;P&gt;책 169페이지 마지막 단락에서 질문입니다 ^^&lt;/P&gt;
&lt;P&gt;&amp;nbsp;&lt;/P&gt;
&lt;P&gt;책에 나온것처럼 쿼리를 실행했습니다.&lt;/P&gt;
&lt;P&gt;&amp;nbsp;&lt;/P&gt;
&lt;P&gt;create table species (grp enum('어류','포유류','조류) not null,&lt;/P&gt;
&lt;P&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; id int not null auto_increment,&lt;/P&gt;
&lt;P&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; name char(30) not null,&lt;/P&gt;
&lt;P&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; primary key (grp,id)&lt;/P&gt;
&lt;P&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; );&lt;/P&gt;
&lt;P&gt;primary key는 테이블에 두개가 존재해도 되는건가요?&lt;/P&gt;
&lt;P&gt;오류메세지는 다음과 같습니다.&lt;/P&gt;
&lt;P&gt;&amp;nbsp;&lt;/P&gt;
&lt;P&gt;Incorrect table definition; there can be only one auto column and it must be defined as a key&lt;/P&gt;
&lt;P&gt;&amp;nbsp;&lt;/P&gt;
&lt;P&gt;&amp;nbsp;&lt;/P&gt;</description>
<author>huber</author>
<pubDate>Thu, 17 May 2007 11:28:19 +0900</pubDate>
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<title>안녕하세요 사용자 추가에 대한 질문입니다.</title>
<link>http://kimho.ohpy.com/3210/34</link>
<description>&lt;P&gt;책 68페이지에 사용자 추가부분이요..&lt;/P&gt;
&lt;P&gt;&amp;nbsp;&lt;/P&gt;
&lt;P&gt;grant all on shopsample.* to &lt;A href=&quot;mailto:kimho@'localhost'&quot; target=_blank&gt;kimho@'localhost'&lt;/A&gt;;&lt;/P&gt;
&lt;P&gt;이렇게 하면 Can't any matching row in the user table 이라고 나옵니다.&lt;/P&gt;
&lt;P&gt;&amp;nbsp;&lt;/P&gt;
&lt;P&gt;책에 있는 그대로 따라했는데 왜 에러가 나는지 모르겠습니다.&lt;/P&gt;
&lt;P&gt;&amp;nbsp;&lt;/P&gt;
&lt;P&gt;또 70페이지 customers 테이블 생성시에 &lt;/P&gt;
&lt;P&gt;CREATE TABLE customers (&lt;BR&gt;&amp;nbsp; customers_id INT(5) NOT NULL AUTO_INCREMENT,&amp;nbsp;&amp;nbsp;# 고객 ID&lt;BR&gt;gender CHAR(1) DEFAULT '' NOT NULL,&amp;nbsp;&amp;nbsp;&amp;nbsp;# 성별&lt;BR&gt;name VARCHAR(32) DEFAULT '' NOT NULL,&amp;nbsp;&amp;nbsp;&amp;nbsp;# 이름&lt;BR&gt;job VARCHAR(30) DEFAULT '' NOT NULL,&amp;nbsp;&amp;nbsp;&amp;nbsp;# 직업&lt;BR&gt;email VARCHAR(35) DEFAULT '' NOT NULL,&amp;nbsp;&amp;nbsp;&amp;nbsp;# email&lt;BR&gt;address VARCHAR(100) DEFAULT '' NOT NULL,&amp;nbsp;&amp;nbsp;# 주소&lt;BR&gt;telephone VARCHAR(14) DEFAULT '' NOT NULL,&amp;nbsp;&amp;nbsp;# 전화번호&lt;BR&gt;registdate DATE DEFAULT NULL,&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;# 가입일자&lt;BR&gt;modifydate&amp;nbsp;TIMESTAMP&amp;nbsp;DEFAULT NULL,&amp;nbsp;&amp;nbsp;&amp;nbsp;# 변경일자&lt;BR&gt;password VARCHAR(12) DEFAULT '' NOT NULL,&amp;nbsp;&amp;nbsp;# 패스워드&lt;BR&gt;PRIMARY KEY (customers_id)&amp;nbsp; &lt;BR&gt;);&lt;/P&gt;
&lt;P&gt;modifydate 칼럼에서 오류가 나서 DEFAULT를 지웠더니 실행은 되더군요..&lt;/P&gt;
&lt;P&gt;&amp;nbsp;&lt;/P&gt;</description>
<author>hubert</author>
<pubDate>Mon, 14 May 2007 11:03:45 +0900</pubDate>
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<title>안녕하세요~ mysql 책에 나와있는 소스가필요합니다</title>
<link>http://kimho.ohpy.com/3210/33</link>
<description>&lt;P&gt;옛날 책이지만 너무 좋아요~ &lt;/P&gt;
&lt;P&gt;근데 create_table.sql과 insert_table.sql은 어디 있는거예요~?&lt;/P&gt;
&lt;P&gt;&amp;nbsp;&lt;/P&gt;
&lt;P&gt;김호님 화이팅 하시구요~ &lt;/P&gt;
&lt;P&gt;책 꾸준히 볼게요~^^&lt;/P&gt;</description>
<author>앞으로</author>
<pubDate>Tue, 12 Dec 2006 10:43:11 +0900</pubDate>
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